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MQT1002  TN2

MODULE 2 : ÉLÉMENTS D’ALGÈBRE

Question 1

VF = C (1 + ni)

14 016 = C (1+3,5 X 0.048)

14 016 = C (1 + 0,168)

14 016 = C (1,168)     14 016  = 12 000

                                    C x 1,168

C = 12 000 $

Question 2

a)  / [pic 1][pic 2]

b)  / [pic 3][pic 4]

c) 5

d) 3 & 2

e)

Question 3

  1. (3 - 2 + 4x -5) + (3 – 4x)[pic 5][pic 6][pic 7]

(3 + 3) + (2) + (4x + 4x) (-5)[pic 8][pic 9][pic 10]

 6 - 2 + 8x – 5[pic 11][pic 12]

  1. (3 - 2 + 4x -5) – (6 + 9 – 3x)[pic 13][pic 14][pic 15][pic 16]

(3 - 2 + 4x -5) + (6 - 9 + 3x)[pic 17][pic 18][pic 19][pic 20]

(3 ) + (- 2+ - 9 ) + (4x + 3x) (-5)[pic 21][pic 22][pic 23]

3 + 7 + 7x + -5[pic 24][pic 25]

  1.    (6 + 9 – 3x) (3 – 4x)[pic 26][pic 27][pic 28]

= (6(3 + (6) (4+ (93(9 33[pic 29][pic 30][pic 31][pic 32][pic 33][pic 34][pic 35][pic 36][pic 37][pic 38]

= 18+ 24 + 27+ 36+ -9+ -12[pic 39][pic 40][pic 41][pic 42][pic 43][pic 44]

= 18+ 51+ 36- 9-12[pic 45][pic 46][pic 47][pic 48][pic 49]

  1. (6 + 9 – 3x) ÷ (3xy)[pic 50]

 [pic 51]

6 +  + -3x = 2y + 3xy – 6y[pic 52][pic 53][pic 54]

3xy     3xy     3xy

Question 4

  1. + 3x -28[pic 55]

7 + -4 = 3, 7 x -4 = -28

+ 3x -28 = (x - 4) (x + 7)[pic 56]

  1.  – 6xy +  = [pic 57][pic 58]

2(3x) (y)

  1. 16 - [pic 59][pic 60]

(4 - ) (4 + )[pic 61][pic 62][pic 63][pic 64]

  1. 3xy – 15ax + 2by – 10ab =

(3xy – 15ax) + (2by-10ab)

3X (y - 5a) + 2b (y – 5a)

(y - 5a) (3x + 2b)

Question 5

         =    [pic 65]

FV = 6000 (1 + 0.04 X [pic 66]

FV = 6000 (1+ 0.03 X [pic 67]

FV = 6000 (1+ 0.06 X [pic 68]

FV = 6000 + 60 + 15 + 120

FV = 6195 $

Question 6

 =  = 1  [pic 69][pic 70][pic 71]

Question 7

 =  =    = [pic 72][pic 73][pic 74][pic 75][pic 76]

Question 8

Question 9

  1.  () =  [pic 77][pic 78][pic 79]

 = [pic 80]

Question 10

VF = PV(1 + [pic 81]

5000 = 2000(1 + [pic 82]

5000 = 2000([pic 83]

5000 = [pic 84]

Log(2.5)/log(1.06) = n

n = 15.72

Question 11

  1. [pic 85]
  2. [pic 86]
  3.  =  = 8 + 4 + -1 = 11[pic 87][pic 88]

  1. [pic 89]

  1. 3  = [pic 90][pic 91]

Question 12

a)

...

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